HOMEWORK HELP THREAD!

[Dogenzaka]

If you're having any trouble on a certain assignment, subject, or just need help with something schooly in particular, come here.

I'll post when I have a question...it's currently slipped my mind.

I thought we greatly needed something like this.

:D

[Azrael]

You got this from me, Dogen, and you know it!

Can we get this stickied by someone so we don't need to bump it from time to time?

[Dogenzaka]

Sticky of this thread would be great.
I personally need lots of help in math, so any provided help would be great.

I'll be back when I think of a question lol.

[Angel]

as long as it goes up to the first part of precal, i can help.

[Azrael]

And if anyone needs help in anything else besides science and math, I guess I can help from time to time!

[Aucune Raison]

yes hi brb i'll copy down my homework questions could you answer them plzzzzz

here're my glasses let's get to werk! O-O

[Angel]

We should have like Homework Helpers you can ask.

Like this for example:

bamak93
Areas of Expertise:
Math
Science
Foreign Language

[Azrael]

Ziz (Areas of Expertise:)
International History
American History
Religion (Catholicism)
Science (to a certain degree)
Math (to a certain degree)

[Nostalgia]

One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.

The first one is g(x) =

x^3 + 2x
x^2 - 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

[Dogenzaka]

Having finished my math for a while, I haven't looked at a math problem in about 5 months.
And it shows.

*clings to Social Studies and English books of sanctification*

x^3 + 2x
x^2 + 4

Most of my math clumsiness comes from not remembering what I was taught. Since I became homeschooled, I admit while it is great, after I finished math, I moved on to other courses planning to pick up the succeeding course later. Therefore, I'd go long periods of time not practicing equations. I finished Alegebra and got an A in it, but I'm looking at your problem and don't remember how to start picking it apart.

That's my problem.

Can someone please step-by-step solve this problem....so I can remember how to do it?

Also what's the "^" for? I don't remember signs very well.

[Angel]

Originally Posted by Vic Viper

One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.

The first one is g(x) =

x^3 + 2x
x^2 + 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

no, domain is all real numbers. if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

as for zero's, i don't think that's possible either.

lol 0 denominators are evil.

Originally Posted by Dogenzaka

Having finished my math for a while, I haven't looked at a math problem in about 5 months.
And it shows.

*clings to Social Studies and English books of sanctification*

Most of my math clumsiness comes from not remembering what I was taught. Since I became homeschooled, I admit while it is great, after I finished math, I moved on to other courses planning to pick up the succeeding course later. Therefore, I'd go long periods of time not practicing equations. I finished Alegebra and got an A in it, but I'm looking at your problem and don't remember how to start picking it apart.

That's my problem.

Can someone please step-by-step solve this problem....so I can remember how to do it?

Also what's the "^" for? I don't remember signs very well.

^=raised to the power of.

i can simplify it, and that's pretty much it.

x+2x
-------
4

3x
---
4

(3/4)x

[Dogenzaka]

if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

You mean, if I take a negative number, like -8, and ^2 it, it's going to be a positive number. Right?

....I'll be back.
Lol.

[Nostalgia]

Originally Posted by bamak93

no, domain is all real numbers. if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

as for zero's, i don't think that's possible either.

lol 0 denominators are evil.

You're absolutely right, but I fucked up in typing the denominator. It was x^2 - 4, not x^2 + 4. Sorry about that. But, with the correction, am I right?

[Angel]

Originally Posted by Vic Viper

You're absolutely right, but I fucked up in typing the denominator. It was x^2 - 4, not x^2 + 4. So, (-2)^2 and (2)^2 make it to be 4 - 4. So, with that correction, am I right?

yes, you are.

@Dogen: Exactly.

x^2=x(x) and if you multiply 2 negatives together, you can't get a negative product.

[Lifes.Lover]

Sorry. I'm in retard math!

If anyone needs help in History, or analytical essays- or even to check their spelling and grammar, that's my specialty.