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[Dogenzaka]

Woot.
We've established ground roots.
Time to build up.
Lol!

I'm currently working on a World History assignment....I'll be back if there are any questions that I've failed to figure out.

If anyone needs help in History, or analytical essays- or even to check their spelling and grammar, that's my specialty.

Why hello thar bff :D

Does anyone know of any good online web tools for homework, studying, flashcards, reviews based on textbooks, etc. etc.?
Public schools usually give you papers with these links to them, but I don't know of any other than sparknotes D:

[Ulti]

Originally Posted by Vic Viper

One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.

The first one is g(x) =

x^3 + 2x
x^2 - 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

[Lifes.Lover]

LOL, usually, you can find on your textbook a link to their website. From there, you can find what they have.

[Angel]

Originally Posted by Ulti

Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

mah goof.

this is true.

[Nostalgia]

Originally Posted by Ulti

Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

Good point. I completely missed that. Thanks.

[Dogenzaka]

LOL, usually, you can find on your textbook a link to their website. From there, you can find what they have.

I'm not looking for an online version of my textbook, I'm looking for like study materials online, like sparknotes, that use reviews, questions, etc. from official textbooks mebbe :v or even just any old study tools online.

[Lifes.Lover]

Well, there's also cliff notes. And I suppose I could go looking.

[Nostalgia]

Here's the 2nd problem that I said I'd post a bit later.

h(y) = (y^3 - 8)(y + 2)^-3. Again, it's asking for the domain and possible zeros.

First, I worked the negative exponent to make it...

y^3 - 8
(y + 2) ^3

0 to any power will be zero, so I think it's safe to say that -2 will not work out, but all other real numbers will. As for the zero, 2^3 is 8, so that's one, and no other number would work, considering that (-2)^3 is -8. Is this correct?

[Angel]

Originally Posted by Vic Viper

Here's the 2nd problem that I said I'd post a bit later.

h(y) = (y^3 - 8)(y + 2)^-3. Again, it's asking for the domain and possible zeros.

First, I worked the negative exponent to make it...

y^3 - 8
(y + 2) ^3

0 to any power will be zero, so I think it's safe to say that -2 will not work out, but all other real numbers will. As for the zero, 2^3 is 8, so that's one, and no other number would work, considering that (-2)^3 is -8. Is this correct?

y^3 - 8
(y+2)^3

y^3 - 8
(y+2)(y^2+2y+4)

y^3 - 8
y^3+4y^2+8y+8

-8
4y^2+8y+8

^in case it needed to be simplified. but yeah, y=2 is the only solution. and domain=[x=(all real numbers), (excluding) -2)

[Nostalgia]

Originally Posted by bamak93

y^3 - 8
(y+2)^3

y^3 - 8
(y+2)(y^2+2y+4)

y^3 - 8
y^3+4y^2+8y+8

-8
4y^2+8y+8

^in case it needed to be simplified. but yeah, y=2 is the only solution. and domain=[x=(all real numbers), (excluding) -2)

Thank you. It didn't ask to be simplified, but factoring it does help to confirm that -2 is to be excluded. y^3 = -8 +8 cancel and 4y^2 (or 16) and 8y (or -16) cancel as well. That helps to bring the entire thing to a close.

[Angel]

oops, coulda simplified further.

-8
4(y^2+2y+2)

-2
y^2+2y+2

[Nostalgia]

As long as I have the domain and zeros, then it's all good.

[Reika Noko]

20. Assume that Y is the dominant allele for the yellow seeds and y is the recessive allele for green seeds. What is the probability that a pea plant with the genotype Yy crossed a pea plant with the genotype yy will have an offspring with the genotype yy?

Does it mean that it would most likely be an offspring with green seeds because the offspring's heredity would be coming from the pea plant with the genotype yy, being a recessive trait? Or am I completely wrong (since I'm not good with math that is included in science)?

[gramp anime scholar]

I don't know why you're having trouble with that. The answer is 50%.


You should have learned these box-like diagrams.

[Aucune Raison]

my mind is kinda blehhh right now so i don't get what you're trying to say, but that queston is simple
you know those heredity squares? just make a square from those two genotypes, then count how many of the yy genotype there are, and the probability is that value/4

ken :-[